Heat a 1 kg metal block with an electric heater and measure how much energy it takes to raise its temperature. Measure the energy with a joulemeter, or work it out from the current and potential difference. Then calculate the specific heat capacity.
Plot temperature against energy transferred. The first readings (grey) are not on the straight line, because the block and thermometer take time to warm up. The line of best fit uses readings from 2 minutes onwards.
ΔE = m c Δθ
Specific heat capacity is the energy needed to raise the temperature of 1 kg of a substance by 1 °C.
Without a joulemeter: P = V × I, then E = P × t.
From the graph of θ against E: gradient = 1 ÷ (m × c), so c = 1 ÷ (m × gradient).
Safety: the heater and block get hot. Do not touch them and let them cool before packing away.
| Material | c / J/kg °C |
|---|---|
| Aluminium | 900 |
| Steel | 450 |
| Copper | 385 |
| Water | 4200 |
A low specific heat capacity means the material heats up quickly. Copper warms up more than twice as fast as aluminium.
They start easy and get harder. Write your answer first, then check it.